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(1+2+3.....n) Sum of n natural numbers, (1^2 + 2^2+3^2 ...... n^2)Sum square of n natural numbers, Sum cube of n natural numbers program in C language .

  Natural numbers program in c language      

         How to make (1+2+3.....n) Sum of n natural numbers, (1^2 + 2^2+3^2 ...... n^2)Sum square of n natural numbers, Sum cube of n natural numbers program in C language. Then today we will know about it through this program ...

   Sum of n natural numbers 

        The Sum of n natural number formula are 1+2+3+....n = n(n+1)/2=(n^2+n)/2. The math.h header file is used in this program because the pow() function is defined in this header file. The function pow() syntax is double pow(double a , double b). The double is a data type in c language and it's also defined as %lf for input. In this program add= (k+x)/2 where are k=n^2 ,x=n.



Output is :

ENTER THE NATURAL NUMBER:6
SUM OF  N NATURAL NUMBER:21


 Sum square of n natural numbers :
        The Sum square of n natural number formula is 12+22+32…….n2 = n(n+1)(2n+1)/6 = (2n3+3n2+n)/6. In this program add= (q+w+x)/6; where are q=3n2, w=2n3 and  x=n.




Output is :

ENTER THE NATURAL NUMBER:4
SUM SQUARE OF  N NATURAL NUMBER:30

Sum cube of n natural numbers :

The Sum cube of n natural number formula is 13+23+33 +…..n3 = [n(n+1)/2]2 or =[(n2 +n)/2]2.In this program add= pow(q,y);  y=2, q = (k+x)/2,and[{ x=n,k=n2 }].







Output is :

ENTER THE NATURAL NUMBER:4
SUM CUBE OF NATURAL NUMBER:100



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