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Age calculating through date of birth program in C language

DATE OF BIRTH PROGRAM IN C LANGUAGE


        Today's date - your date of birth = your current age 


There are fifth condition are happening..

@1.IF today date 13.7.2021 and date of birth 15.9.2001 age are (2021-2001).(7-9).(13-15) = 20.-2.-2   but it's wrong real age will be 19year.9month.28days .Then first condition will be (days < 0)&&(month<0)


@2.IF today date 13.7.2021 and date of birth 12.9.2001 age are(2021-2001).(7-9).(13-12) = 20.-2.1 but it's wrong real age will be 19 year . 10 month . 1 days .Then  second condition will be (days>0)&&(month<0).


@3.IF today date 13.7.2021 and date of birth 13.9.2001 age are(2021-2001).(7-9).(13-13) = 20.-2.0 but it's wrong real age will be 19 year . 10 month . 0days .Then  third condition will be (days==0)&&(month<0).

@4.IF today date 13.7.2021 and date of birth 13.9.2001 age are(2021-2001).(7-9).(13-13) = 20.1.0 but it's wrong real age will be 19 year . 10 month . 0days .Then  fourth condition will be (days<=0)&&(month>=0).

@5.IF today date 13.7.2021 and date of birth 15.6.2001 age are(2021-2001).(7-6).(13-13) = 20.1.but it's wrong real age will be 19 year . 10 month . 0days .Then  fourth condition will be (days<0)&&(month>=0).

In C language 
 IF STATEMENT SYNTAX  IN THIS PROGRAM
    if(condition)
    {
             if(condition)
            {    
                    statements;
             }
      }

PROGRAM


  OUTPUT ARE :

Enter your date of birth(DD.MM.YY):15
6
2002
Enter the today date(DD.MM.YY):14
7
2021
YOUR AGE ARE :29 DAYS 0 MOMTH 19 YEAR








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